The self-inductance of a coil is 0.8 H. If current changes from 0 to 4 A in 0.4 s, find induced emf.
Q1. The self-inductance of a coil is 0.8 H. If current changes from 0 to 4 A in 0.4 s, find induced emf.
Answer: 8 V
Explanation: ε = -L(dI/dt) = -0.8 * (4 / 0.4) = 8 V.