A coil has 300 turns and flux linkage 0.02 Wb. If current is 3 A, find self-inductance.
Question 1
Q1. A coil has 300 turns and flux linkage 0.02 Wb. If current is 3 A, find self-inductance.
Answer: 2 H
Explanation: L = Nϕ/I = 300 * 0.02 / 3 = 2 H.