The flux linked with a coil is given by ϕ = 2t² + 4t + 6. The induced emf at t = 1 / 2 s is
Q1. The flux linked with a coil is given by ϕ = 2t² + 4t + 6. The induced emf at t = 1 / 2 s is
Answer: 6 V
Explanation: ε = -dϕ/dt = -(4t + 4), at t = 1/2, ε = -(4 * 1/2 + 4) = -6 V, magnitude is 6 V.