The current in a coil changes from 1 A to 2 A in 0.1 s. If the induced emf is 10 V, the self-inductance is
Q1. The current in a coil changes from 1 A to 2 A in 0.1 s. If the induced emf is 10 V, the self-inductance is
Answer: 1 H
Explanation: ε = -L(dI/dt), 10 = L * (2-1)/0.1, L = 1 H.