A 50 Hz AC source is connected to a capacitor. The current is 1 A when the capacitance is 10 μF. If the frequency is doubled, what is the new capacitance required to maintain the same current?
Q1. A 50 Hz AC source is connected to a capacitor. The current is 1 A when the capacitance is 10 μF. If the frequency is doubled, what is the new capacitance required to maintain the same current?
Answer: 5 μF
Explanation: I = V/X_C = V/(1/(2πfC)) = 2πfCV. If f is doubled, C must be halved to maintain the same I