engineering physics MCQ #144

An AC source of voltage 100 V and frequency 50 Hz is connected to a circuit having R = 10 Ω and L = 1 H in series. The current is

engineering physics MCQ #144

  1. Question 1

    Q1. An AC source of voltage 100 V and frequency 50 Hz is connected to a circuit having R = 10 Ω and L = 1 H in series. The current is

    • A) 0.29 A
    • B) 0.58 A
    • C) 1 A
    • D) 2 A

    Answer: 0.58 A

    Explanation: X_L = 2πfL = 314 Ω. Z = √(R² + X_L²) = √(10² + 314²) = 314.16 Ω. I = V/Z = 100/314.16 = 0.318 A, approx. 0.29-0.32 due to rounding