The voltage across an inductor is given by V = 100 sin(100πt). If the inductance is 1 H, the current is
Q1. The voltage across an inductor is given by V = 100 sin(100πt). If the inductance is 1 H, the current is
Answer: 0.318 sin(100πt - π/2)
Explanation: I = (1/L) ∫V dt = (1/1) ∫100 sin(100πt) dt. After integration, I = 0.318 sin(100πt - π/2)