In an AC circuit, voltage and current are given by V = 200 sin(100πt) and I = 5 sin(100πt + π/3). Find power dissipated.
Q1. In an AC circuit, voltage and current are given by V = 200 sin(100πt) and I = 5 sin(100πt + π/3). Find power dissipated.
Answer: 433 W
Explanation: Use P = Vrms * Irms * cos(φ), where Vrms = Vpeak/√2, Irms = Ipeak/√2, and φ is the phase difference between V and I.