engineering physics MCQ #180

The average power dissipated in an AC circuit over a cycle is

engineering physics MCQ #180

  1. Question 1

    Q1. The average power dissipated in an AC circuit over a cycle is

    • A) Vrms * Irms
    • B) Vrms * Irms * cos(φ)
    • C) Vrms * Irms * sin(φ)
    • D) 0

    Answer: Vrms * Irms * cos(φ)

    Explanation: Average power = Vrms * Irms * cos(φ), where φ is the phase difference between voltage and current.