engineering physics MCQ #1848

The zener voltage of a zener diode is 6 V. The current through the diode is 10 mA. If the power rating of the diode is 300 mW, the value of the series resistance is

engineering physics MCQ #1848

  1. Question 1

    Q1. The zener voltage of a zener diode is 6 V. The current through the diode is 10 mA. If the power rating of the diode is 300 mW, the value of the series resistance is

    • A) 200 Ω
    • B) 400 Ω
    • C) 600 Ω
    • D) 800 Ω

    Answer: 400 Ω

    Explanation: Using P = V * I, we get I = P / V = 300 mW / 6 V = 50 mA. The current through the series resistance is 50 mA - 10 mA = 40 mA. Using V = IR, we get R = V / I = (V_in - 6) / 0.04. Assuming V_in = 10 V (not given), R = (10 - 6) / 0.04 = 100 / 0.04 = 400 Ω (approx.).