engineering physics MCQ #1854

A diode having a forward resistance of 50 Ω is used for half-wave rectification. The input voltage is 220 V (rms). The load resistance is 1 kΩ. The output dc current is

engineering physics MCQ #1854

  1. Question 1

    Q1. A diode having a forward resistance of 50 Ω is used for half-wave rectification. The input voltage is 220 V (rms). The load resistance is 1 kΩ. The output dc current is

    • A) 0.198 A
    • B) 0.099 A
    • C) 0.297 A
    • D) 0.396 A

    Answer: 0.099 A

    Explanation: Idc = Im / π = Vm / (π * (Rf + Rl)) = 220√2 / (π * (50 + 1000)) = 0.099 A.