engineering physics MCQ #1872

A diode having internal resistance 20 Ω is used for half-wave rectification. If the applied voltage is v = 50 sin(πt), the peak current is

engineering physics MCQ #1872

  1. Question 1

    Q1. A diode having internal resistance 20 Ω is used for half-wave rectification. If the applied voltage is v = 50 sin(πt), the peak current is

    • A) 1.25 A
    • B) 2.5 A
    • C) 1 A
    • D) 2 A

    Answer: 2.5 A

    Explanation: Peak current = Vpeak / (Rf + R), where Rf = 20 Ω and Vpeak = 50 V, so Ipeak = 50 / 20 = 2.5 A.