The cutoff frequency of an RC low-pass filter is given by f_c = 1 / (2πRC). What happens to f_c if R is doubled?
Q1. The cutoff frequency of an RC low-pass filter is given by f_c = 1 / (2πRC). What happens to f_c if R is doubled?
Answer: f_c is halved
Explanation: f_c is inversely proportional to R, so doubling R halves f_c.