A series LCR circuit has L = 0.1 H, C = 10^-6 F, and R = 100 Ω. Find resonant frequency.
Q1. A series LCR circuit has L = 0.1 H, C = 10^-6 F, and R = 100 Ω. Find resonant frequency.
Answer: 1591 Hz
Explanation: Use f = 1 / (2π√(LC)), where L = 0.1 H and C = 10^-6 F. So, f = 1 / (2π√(0.1 * 10^-6)) = 1591 Hz.