An inductor of 0.5 H is connected to an AC source. If current is 2 A and voltage is 200 V, find frequency.
Q1. An inductor of 0.5 H is connected to an AC source. If current is 2 A and voltage is 200 V, find frequency.
Answer: 31.83 Hz
Explanation: Use V = I * Xl, where Xl = 2πfL. So, f = V / (2πIL) = 200 / (2π * 2 * 0.5) = 31.83 Hz.