A series LCR circuit is in resonance. If C = 10^-6 F and L = 0.1 H, find angular frequency.
Q1. A series LCR circuit is in resonance. If C = 10^-6 F and L = 0.1 H, find angular frequency.
Answer: 3162 rad/s
Explanation: Use ω = 1 / √(LC), where L = 0.1 H and C = 10^-6 F. So, ω = 1 / √(0.1 * 10^-6) = 3162 rad/s.