engineering physics MCQ #212

An AC source is connected to a 10 Ω resistor. If rms current is 2 A, find average power dissipated.

engineering physics MCQ #212

  1. Question 1

    Q1. An AC source is connected to a 10 Ω resistor. If rms current is 2 A, find average power dissipated.

    • A) 20 W
    • B) 40 W
    • C) 80 W
    • D) 0 W

    Answer: 40 W

    Explanation: Use P = I²rms * R, where Irms = 2 A and R = 10 Ω. So, P = (2)² * 10 = 40 W.