A capacitor of 100 μF is connected to an AC source of 50 Hz. Find capacitive reactance.
Q1. A capacitor of 100 μF is connected to an AC source of 50 Hz. Find capacitive reactance.
Answer: 31.83 Ω
Explanation: Use Xc = 1 / (2πfC), where f = 50 Hz and C = 100 μF. So, Xc = 1 / (2π * 50 * 100 * 10^-6) = 31.83 Ω.