engineering physics MCQ #225

The average power dissipated in an AC circuit is given by

engineering physics MCQ #225

  1. Question 1

    Q1. The average power dissipated in an AC circuit is given by

    • A) Vrms * Irms
    • B) Vrms * Irms * cos(φ)
    • C) Vrms * Irms * sin(φ)
    • D) Vrms + Irms

    Answer: Vrms * Irms * cos(φ)

    Explanation: Average power P = Vrms * Irms * cos(φ), where φ is the phase angle between voltage and current.