In an AC circuit, the current is given by I = 5 sin(100πt - π/2). The time taken by the current to reach its peak value will be
Q1. In an AC circuit, the current is given by I = 5 sin(100πt - π/2). The time taken by the current to reach its peak value will be
Answer: 1 / 50 s
Explanation: ω = 100π, so T = 2π / ω = 1 / 50. Time to reach peak = T/4 = 1 / 200 s, but given the phase shift, it's 1/50 s.