A series LCR circuit has R = 10 Ω, L = 0.1 H, and C = 100 μF. The resonance frequency is
Q1. A series LCR circuit has R = 10 Ω, L = 0.1 H, and C = 100 μF. The resonance frequency is
Answer: 50 / π Hz
Explanation: f = 1 / (2π √(LC)) = 1 / (2π √(0.1 * 100e-6)) = 50 / π Hz.