engineering physics MCQ #263

What is the average power consumed in an AC circuit with Irms = 2 A and Vrms = 100 V, if the phase angle is 60°?

engineering physics MCQ #263

  1. Question 1

    Q1. What is the average power consumed in an AC circuit with Irms = 2 A and Vrms = 100 V, if the phase angle is 60°?

    • A) 100 W
    • B) 200 W
    • C) 100 √3 W
    • D) 200 cos(60°) W

    Answer: 100 √3 W

    Explanation: The average power P = Vrms * Irms * cosφ, so P = 100 * 2 * cos(60°) = 100 W.