engineering physics MCQ #267

An AC source with emf E = E₀ sin(ωt) is connected to a capacitor. What is the expression for current?

engineering physics MCQ #267

  1. Question 1

    Q1. An AC source with emf E = E₀ sin(ωt) is connected to a capacitor. What is the expression for current?

    • A) I = (E₀ / Xc) sin(ωt)
    • B) I = (E₀ / Xc) sin(ωt + π/2)
    • C) I = (E₀ / Xc) cos(ωt)
    • D) I = (E₀ / Xc) cos(ωt + π/2)

    Answer: I = (E₀ / Xc) sin(ωt + π/2)

    Explanation: The current in a capacitive circuit leads the voltage by 90°, so I = (E₀ / Xc) sin(ωt + π/2).