The efficiency of a Carnot engine is 50%. The temperature of the sink is 27°C. The temperature of the source is
Q1. The efficiency of a Carnot engine is 50%. The temperature of the sink is 27°C. The temperature of the source is
Answer: 327°C
Explanation: Efficiency = 1 - (T_sink / T_source). Given efficiency = 0.5, T_sink = 300K, we can solve for T_source = 600K or 327°C.