engineering physics MCQ #2764

The efficiency of a Carnot engine is 1 / 2. If the sink temperature is 300 K, the source temperature is

engineering physics MCQ #2764

  1. Question 1

    Q1. The efficiency of a Carnot engine is 1 / 2. If the sink temperature is 300 K, the source temperature is

    • A) 300 K
    • B) 400 K
    • C) 500 K
    • D) 600 K

    Answer: 600 K

    Explanation: Efficiency = 1 - (T_sink / T_source). Given efficiency = 1 / 2 and T_sink = 300 K, we get 1 / 2 = 1 - (300 / T_source), so T_source = 600 K.