engineering physics MCQ #2778

For a given process, the heat absorbed is 100 J and the work done is 50 J. The change in internal energy is

engineering physics MCQ #2778

  1. Question 1

    Q1. For a given process, the heat absorbed is 100 J and the work done is 50 J. The change in internal energy is

    • A) 50 J
    • B) 150 J
    • C) 200 J
    • D) -50 J

    Answer: 50 J

    Explanation: ΔU = Q - W = 100 J - 50 J = 50 J, applying the first law of thermodynamics.