A capacitor of capacitance 100 μF is connected to an AC source of 100 V, 50 Hz. Find the capacitive reactance.
Q1. A capacitor of capacitance 100 μF is connected to an AC source of 100 V, 50 Hz. Find the capacitive reactance.
Answer: 318.3 Ω
Explanation: Capacitive reactance Xc = 1 / (2πfC) = 1 / (2 * 3.14159 * 50 * 100 * 10^(-6)) = 1 / 0.0314159 = 31.83 Ω.