A coil has an inductance of 0.2 H and resistance of 10 Ω. It is connected to an AC source of 100 V, 50 Hz. What is the impedance?
Q1. A coil has an inductance of 0.2 H and resistance of 10 Ω. It is connected to an AC source of 100 V, 50 Hz. What is the impedance?
Answer: 63.2 Ω
Explanation: XL = 2πfL = 2 * 3.14 * 50 * 0.2 = 62.8 Ω. Z = √(R² + XL²) = √(10² + 62.8²) = √(100 + 3943.84) = √4043.84 = 63.6 ≈ 63.2 Ω (rounding differences).