A series LCR circuit is in resonance. If the capacitance is doubled, what happens to the resonant frequency?
Q1. A series LCR circuit is in resonance. If the capacitance is doubled, what happens to the resonant frequency?
Answer: It becomes 1/√2 times
Explanation: f = 1 / (2π√LC). If C is doubled, f becomes 1 / √(2C) = 1/√2 times the original frequency.