A coil has an inductance of 0.1 H and resistance of 10 Ω. It is connected to an AC source of 100 V, 50 Hz. The impedance is
Q1. A coil has an inductance of 0.1 H and resistance of 10 Ω. It is connected to an AC source of 100 V, 50 Hz. The impedance is
Answer: 33.3 Ω
Explanation: XL = 2πfL = 2π * 50 * 0.1 = 31.4 Ω, Z = √(R² + XL²) = √(10² + 31.4²) = 33.3 Ω.