The energy of the photon emitted when an electron jumps from n = 4 to n = 2 is
Question 1
Q1. The energy of the photon emitted when an electron jumps from n = 4 to n = 2 is
Answer: 2.55 eV
Explanation: Using ΔE = 13.6 * (1 / 2² - 1 / 4²), we get ΔE = 2.55 eV.