The frequency of radiation emitted when an electron jumps from n = 3 to n = 2 is given by ΔE = hν. What is ν?
Q1. The frequency of radiation emitted when an electron jumps from n = 3 to n = 2 is given by ΔE = hν. What is ν?
Answer: 4.57 * 10¹⁴ Hz
Explanation: ΔE = E3 - E2 = -1.51 - (-3.4) = 1.89 eV. ν = ΔE / h = 1.89 * 1.6 * 10⁻¹⁹ / (6.63 * 10⁻³⁴) = 4.57 * 10¹⁴ Hz.