The energy of the photon emitted when an electron jumps from n = 4 to n = 2 is?
Question 1
Q1. The energy of the photon emitted when an electron jumps from n = 4 to n = 2 is?
Answer: 2.55 eV
Explanation: ΔE = E4 - E2 = (-0.85) - (-3.4) = 2.55 eV.