engineering physics MCQ #3681

A projectile is launched at 45°. What is its range if initial velocity is 20 m/s?

engineering physics MCQ #3681

  1. Question 1

    Q1. A projectile is launched at 45°. What is its range if initial velocity is 20 m/s?

    • A) 20 m
    • B) 40 m
    • C) 40.8 m
    • D) 80 m

    Answer: 40.8 m

    Explanation: Range = (u² sin(2θ)) / g = (20² * sin(90°)) / 9.8 = 400 / 9.8 = 40.8 m, using the range formula.