engineering physics MCQ #3691

A 5 kg block is moving on a frictionless surface with 10 m/s velocity. What is the force required to stop it in 2 s?

engineering physics MCQ #3691

  1. Question 1

    Q1. A 5 kg block is moving on a frictionless surface with 10 m/s velocity. What is the force required to stop it in 2 s?

    • A) 25 N
    • B) -25 N
    • C) 50 N
    • D) -50 N (opposite direction)

    Answer: 25 N

    Explanation: F = ma = m * Δv / Δt = 5 * 10 / 2 = 25 N, applying Newton's second law to find the required force.