engineering physics MCQ #3692

A 2 kg block is moving with 5 m/s velocity on a frictionless surface. What is its momentum?

engineering physics MCQ #3692

  1. Question 1

    Q1. A 2 kg block is moving with 5 m/s velocity on a frictionless surface. What is its momentum?

    • A) 10 kg m/s
    • B) 5 kg m/s
    • C) 2 kg m/s
    • D) 0 kg m/s

    Answer: 10 kg m/s

    Explanation: Momentum = mass * velocity = 2 kg * 5 m/s = 10 kg m/s, using the formula p = mv.