A 2 kg block is attached to a spring with spring constant 100 N/m. What is its frequency?
Q1. A 2 kg block is attached to a spring with spring constant 100 N/m. What is its frequency?
Answer: √(100 / 2) / (2 * π)
Explanation: Frequency = (1 / (2 * π)) * √(k / m) = √(100 / 2) / (2 * π).