engineering physics MCQ #3702

A body is projected upwards with 45° angle. What is its horizontal velocity component?

engineering physics MCQ #3702

  1. Question 1

    Q1. A body is projected upwards with 45° angle. What is its horizontal velocity component?

    • A) v * cos(45°)
    • B) v * sin(45°)
    • C) v
    • D) 0

    Answer: v * cos(45°)

    Explanation: Horizontal component = v * cos(θ) = v * cos(45°).