engineering physics MCQ #3708

A 5 kg block is moving with 10 m/s on a frictionless surface. What force is required to stop it in 2 s?

engineering physics MCQ #3708

  1. Question 1

    Q1. A 5 kg block is moving with 10 m/s on a frictionless surface. What force is required to stop it in 2 s?

    • A) 25 N
    • B) -25 N
    • C) 50 N
    • D) -50 N

    Answer: -25 N

    Explanation: F = ma = m * (v - u) / t = 5 * (0 - 10) / 2 = -25 N, using Newton's second law of motion.