A 2 kg block is attached to a spring with k = 100 N/m. If it is displaced by 0.2 m, what is its acceleration?
Q1. A 2 kg block is attached to a spring with k = 100 N/m. If it is displaced by 0.2 m, what is its acceleration?
Answer: 10 m/s²
Explanation: F = -kx = ma, a = -kx / m = -100 * 0.2 / 2 = -10 m/s², using Hooke's law and F = ma.