The Balmer series corresponds to transitions to n = 2. What is the wavelength of the second line?
Q1. The Balmer series corresponds to transitions to n = 2. What is the wavelength of the second line?
Answer: 486 nm
Explanation: For the second line, n = 4 to n = 2, using 1 / λ = R * (1 / 2² - 1 / 4²) gives λ = 486 nm.