engineering physics MCQ #377

The frequency of the emitted radiation when an electron jumps from n = 3 to n = 2 is given by ΔE = hf. What is the frequency?

engineering physics MCQ #377

  1. Question 1

    Q1. The frequency of the emitted radiation when an electron jumps from n = 3 to n = 2 is given by ΔE = hf. What is the frequency?

    • A) 4.57 * 10^14 Hz
    • B) 3.29 * 10^15 Hz
    • C) 6.17 * 10^14 Hz
    • D) 2.47 * 10^15 Hz

    Answer: 4.57 * 10^14 Hz

    Explanation: Calculate ΔE = E3 - E2 = -1.51 eV - (-3.4 eV) = 1.89 eV, then f = ΔE / h.