The ratio of the energies of the first two excited states of hydrogen atom is
Q1. The ratio of the energies of the first two excited states of hydrogen atom is
Answer: 4/9
Explanation: Using En = -13.6 / n² eV, E2 = -3.4 eV and E3 = -1.51 eV, ratio is E2/E3 = 4/9 (in magnitude).