The ratio of the wavelengths of the last line of Lyman series and the last line of Balmer series is
Q1. The ratio of the wavelengths of the last line of Lyman series and the last line of Balmer series is
Answer: 1/4
Explanation: Using 1/λ = R [1/n1² - 1/n2²], ratio of wavelengths is calculated as λ_Lyman / λ_Balmer = (1/4) / 1 = 1/4.