engineering physics MCQ #389

The energy of the photon emitted when an electron jumps from n = 4 to n = 2 in hydrogen atom is

engineering physics MCQ #389

  1. Question 1

    Q1. The energy of the photon emitted when an electron jumps from n = 4 to n = 2 in hydrogen atom is

    • A) 2.55 eV
    • B) 1.89 eV
    • C) 3.4 eV
    • D) 4.25 eV

    Answer: 2.55 eV

    Explanation: Using En = -13.6 / n² eV, ΔE = E4 - E2 = -0.85 - (-3.4) = 2.55 eV.