The energy of the photon absorbed when an electron jumps from n = 2 to n = 3 is given by ΔE = 13.6 [1/2² - 1/3²] eV. What is ΔE?
Q1. The energy of the photon absorbed when an electron jumps from n = 2 to n = 3 is given by ΔE = 13.6 [1/2² - 1/3²] eV. What is ΔE?
Answer: 1.89 eV
Explanation: ΔE = 13.6 [1/4 - 1/9] = 13.6 * (5/36) = 1.89 eV.