engineering physics MCQ #402

The ionization energy of Li++ is

engineering physics MCQ #402

  1. Question 1

    Q1. The ionization energy of Li++ is

    • A) 13.6 eV
    • B) 54.4 eV
    • C) 122.4 eV
    • D) 13.6 * 9 eV

    Answer: 122.4 eV

    Explanation: Ionization energy is proportional to Z². For Li++, Z = 3, so ionization energy = 13.6 * 3² = 122.4 eV.