engineering physics MCQ #412

The ionization energy of hydrogen atom is 13.6 eV. The energy required to remove an electron from n = 2 is

engineering physics MCQ #412

  1. Question 1

    Q1. The ionization energy of hydrogen atom is 13.6 eV. The energy required to remove an electron from n = 2 is

    • A) 3.4 eV
    • B) 6.8 eV
    • C) 13.6 eV
    • D) 1.7 eV

    Answer: 3.4 eV

    Explanation: Energy required = -En = -(-13.6 / 2²) = 3.4 eV.