engineering physics MCQ #432

The frequency of revolution of the electron in the nth orbit is given by fn = me⁴ / (4ε0²n³h³). What is the frequency of revolution of the electron in the 2nd orbit?

engineering physics MCQ #432

  1. Question 1

    Q1. The frequency of revolution of the electron in the nth orbit is given by fn = me⁴ / (4ε0²n³h³). What is the frequency of revolution of the electron in the 2nd orbit?

    • A) me⁴ / (32ε0²h³)
    • B) me⁴ / (64ε0²h³)
    • C) me⁴ / (128ε0²h³)
    • D) me⁴ / (256ε0²h³)

    Answer: me⁴ / (32ε0²h³)

    Explanation: Substitute n = 2 in the given formula to get f2 = me⁴ / (32ε0²h³).