The energy of the nth orbit of hydrogen atom is given by E_n = -13.6 / n² eV. The energy of the 2nd orbit is
Q1. The energy of the nth orbit of hydrogen atom is given by E_n = -13.6 / n² eV. The energy of the 2nd orbit is
Answer: -3.4 eV
Explanation: Substitute n = 2 in E_n = -13.6 / n² eV to get E_2 = -13.6 / 4 = -3.4 eV.